So I've never did a boost converter circuit before. I have this 3 volt watch batter I'm gonna use to power my infrared device. I'm gonna turn 3V battery into 3.3V steady DC. I'm laying out the circuit right now and I'm stumped.
The data sheet shows a circuit for a 5V boost. I bought the 3.3Volt boost model of the chip. On the 5V circuit, it shows a pin called LX attached to output with a Schottky diode (whatever that is). It says no need for diode in 3.3V circuit.
Do I take the diode out and break the circuit between Vout and LX pins? Or... Do I take the diode out and connect the Vout and LX pins with a trace?
This is the component I'm using, the AS1325 for 3.3V.