Led Matrix Circuit

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#1
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I am doing a test circuit for 8x24 led Matrix display using 3 8x8 led matrix modules.
I want to know the row and column driver circuits to source and sink the driving current for all thses leds.
I am using a shift register for columns and 8 pins for row selection.

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More info required. Voltages, currents, power dissipation, etc.

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I have a 5v 2A dc power supplay. About the power, I do not have a view except that I will use the normal 8x8 led matrix module and I will use 3 of them.

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As has been mentioned, you are missing a whole lot of information, but I'll take a try at it anyway.

The first assumption I'll make is that you are using LED modules that use an average current of 10mA per LED. That gives a moderate brightness, but you may need more or less than that.
The second assumption I'll make is that the display is organized as eight rows of 24 columns.

With eight rows, each row is on for 1/8 of the time. To get the correct brightness, the current in each column must be eight times as much as the average LED current, or 80 mA per column. The
TPIC6C596 power shift register can sink this much current, so three of them would handle your column driver needs. You'll also need a resistor to limit the current in each column. It's not possible to work out the exact value without knowing more about the LED modules, but something near 50 ohms sounds about right.
The row drivers are a bit harder to deal with. The current requirements of each row will vary depending on how many LEDs in that row are on. The worst case situation would be where all 24 LEDs are on, in which case the row driver needs to handle 24x80mA or 1.92 amps. I would suggest a set of P channel mosfet transistors for the power drivers, and select the active row by taking the gate of the transistor low.
Driving the mosfets with a 74138 type data selector would ensure that you never have more than one row active at any given time.

For anything much more than that, you'll have to provide more information. If you have the part number from the display, it would be a start.