Hi.
I just found out that char is unsigned. Tricky that. I had to write signed char to get what I wanted. (Imagecraft but it should be ANSII C). Somethere deep in the back of my brain I think I had this information stored but it had to be refreshed.
I also found that running a for loop from n to 0 saves 1 word. That was how I found it, the test for i>=0 never ended.
/Bengt
I just found out that char is unsigned.
My experience is that char is usually signed, which always struck me as a bit odd (excuse pun).
Just to note that most GCC Makefiles will tend to include:
CFLAGS += -funsigned-char
to remove any doubt about this. Maybe Imagecraft has an option for force how it should be interpreted.
Note however that even with -funsigned-char (which forces "char c" to be interpreted as "unsigned char c") that if you use a character or string literal it remains as implied type "char" and is neither signed nor unsigned.
Cliff
The ImageCraft documentation is quite explicit about char being unsigned: page 20, "Converting from other ANSI C Compilers" bullet point 1 - "Our char data type is unsigned"
Just out of interest does Imagecraft have stdint.h? If it did then using uint8_t or int8_t makes it completely unequivocal as to the exact type (and width) of a variable (which is, of course, their raison d'etre)
Of course library functions like strcpy() will still moan as they are looking for "char *" etc.
