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PhysicsQ&A LibraryA moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done W in terms of K1? Solution To solve for the work done, first we must determine what is the final kinetic energy of the electron. By concept, we know that K1=(1/2)mv²1 K2=(1/2)mv2 But it was mentioned that: V2=( V1 so, K2 in terms of v1 is K2=( )mv21 Substituting the expression for Kj results to K2=( )K1 Since work done is W=AK=K -K Evaluating results to W=( )K1Start your trial now! First week only $4.99!*arrow_forward*

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