Some 16-bit number cumputes in my program, and then it must be written into OCR1A 8-bit register. So, I need to convert uint16_t to uint8_t.
uint16_t A = 120;
uint8_t B;
Simple B = A doesn't work.
Naturally, I need lower part of 16-bit number.
What should I do?
Thanks :-)
Simple B = A doesn't work.
OCR1A = A; will work as long as A <= 255.
Don
You can cast it to kill the upper-byte of the 16-bit variable:
uint16_t A = 120; uint8_t B; B = (uint8_t)A; // Get lower byte of 16-bit var
If you need the upper byte, shift and cast instead:
uint16_t A = 120; uint8_t B; B = (uint8_t)(A >> 8); // Get upper byte of 16-bit var
- Dean :twisted:
You can cast it to kill the upper-byte of the 16-bit variable:uint16_t A = 120; uint8_t B; B = (uint8_t)A; // Get lower byte of 16-bit var
Don
Self commenting code. Once bitten twice shy ;).
- Dean :twisted:
Removed spam.
Vish, do this one more time and you'll be reported. Its useless digging up old posts just so you can advertise your blog. Just stop it.
He's been doing it everywhere:
https://www.google.ca/search?q=embeddedcubes#q=embeddedcubes&nfpr=1
http://stackoverflow.com/questions/11069108/uint32-t-does-not-name-a-type
Looks like his comments have been purged from the two stackoverflow.com threads, CTRL-F for 'cubes' found nothing.
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